NAME :
PHYSICS 4A ----QUIZ 0
- You have a right triangle
whose hypotenuse is of length A and one angle is given as q . Find the length of the other two
sides B and C in terms of A and q .

Answer : B = cosq and C=sin q
(The angle q was supposed to be
between sides A and B. I forgot to put this in the diagram).
- You know that sinq =1/2. Without using a calculator find
cosq .
Answer : cos q =Ö (1-sin2q ) = Ö (1-0.25)=Ö
.75=0.866
- Assuming that a,b,c
are known constants solve for x in the equation
(a/x)+b = (c/x).
Answer : a+ b x = c à bx = c-a à x = (c-a)/b
- What does ln(e2.67)
equal ? (don't use your calculator)
Answer : It equals 2.67 (ln "eats" e).
- Solve the system of equations
for x and y ?
3x +5y =14
-x -6y = -9
Answer : x=3 ; y = 1
- Find the derivative (df/dx)
for
(a) f(x) = a + bÖ
x +c e-x
(b) f(x) = a cos (bx2)
(a) df/dx = b/(2 Ö x) - c e-x
(b) df/dx = -2ab x sin (bx2)
- Find the integral (ò f(x) dx) for the functions below
- f(x) = b x3
- f(x) = a sin(bx +c)
Answer : (a) ò f(x) dx =
(b/4) x4
(b) ò f(x) dx = -(a/b) cos
(bx +c)
- For the function y(x) = x(1-x2
) find
- The maximum of this function
- The area under the curve
between the two points where it crosses the x-axis.
Answer : (a) dy / dx = 1 - 3 x2 = 0 à xmax=1/Ö 3=.0577
- y=0 at x=0 and x=1 (also
it crosses at x=-1 which I didn't consider)
so ò 01 x(1-x2)
dx = (1/2) x2 - (1/4) x4 |01 =
(1/2) - (1/4) - 0 +0 = 1/4 =0.25